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4x^2-x^2-143=0
We add all the numbers together, and all the variables
3x^2-143=0
a = 3; b = 0; c = -143;
Δ = b2-4ac
Δ = 02-4·3·(-143)
Δ = 1716
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1716}=\sqrt{4*429}=\sqrt{4}*\sqrt{429}=2\sqrt{429}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{429}}{2*3}=\frac{0-2\sqrt{429}}{6} =-\frac{2\sqrt{429}}{6} =-\frac{\sqrt{429}}{3} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{429}}{2*3}=\frac{0+2\sqrt{429}}{6} =\frac{2\sqrt{429}}{6} =\frac{\sqrt{429}}{3} $
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